Tcs Aptitude Placement Papers - Tcs Aptitude Interview Questions and Answers updated on 19.Mar.2024

The Answer is 2@First he will select 24 in that the maximum chance is all are red so if we take one more socks, it has to be the other color. Hence, the answer is 24 + 1 = 25

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

 P(E) =n(E)/n(S)=9/20

One number be x and other y, then  x - y = 9

(x - y)2 = 81

x2 + y2 = 81 + 2xy = 109

(x+y)2 = x2 + y2 + 2xy = 109 + 28 = 137

So answer is 137

a: b = 3:5

b: c =   8: 5

a:b:c  = 24 : 40 : 25  and total is 24+40+25 = 89 

(40/89) x 35 = 15.73

(3/4)t=1

t=4/3=1+1/3

She will have to increase her speed by 33.333% to run the same distance in 3/4s of the time

1= 5^4-1=125, n= no of digits

1 2

2 4

3 2

4 4

5 2

The first two digits in the place can be filled in 5 x 5 ways.

So there are totally 25 x 5 = 125 ways

Have 6 mice for testing,

Give each mice contents from 5 cans each

5 5 5 5 5 5

After 14 hours, one of the mice will die

So, we will know which 5 cans must have the poison

Then , take the contents of these 5 cans and give to the remaining 5 mice each.

We will know in due time which can is poisoned

5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30

Let the age be the friends be 2x and 3x. Sum of their ages = 55

2x + 3x = 55 => 5x=55 => x=11

Their ages are 22 and 33

After k years both of them will be 22+k and 33+k years old

Ratio of their age at that time will me 4:5

(22+k)/(33+k)=4/5 

5(22+k)=4(33+4) => 110 + 5k = 132+4k

K=132-110 = 22

Probability for the bacteria to be dying = 1/3

Hence probability of survival = 1/5

if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5)

Probability of bacteria to die is 1/3

or its get tripled, hence the probability of getting tripled is (2/3)*p*p*p that is  (2/3)*p^3

so both the probability combined as P=1/3+(2/3*p^3)

Let the capacity of the tank be 6 litre.

Then time to fill this tank is 6 hour ,when there is no leakage .

so in 1 hour it fills 1 litre.

when leakage is there then it takes 6.5 hour to fill 6 litre 

so in 1 hour it fills 6/6.5 litre.

Time to vacate will be 1-(6/6.5) = 1/13 litre in 1 hour

time to vacate 1 litre will be 13 hour.

For 6 litre it will be 13*6 =78 

Speed = 54 x5/18 m/sec = 15 m/sec.

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then,x + 300/36 = 15

 x + 300 = 540

 x = 240 m.

Dimensions = 4 x 5 x 2

TSA = 2 (4 x 5 + 5 x 2 + 4 x 2) = 2(20+10+8)=2x38 =  76 sq m

So bricks required = 76 x 17 = 1292

For 5 rooms 1292 x5 = 6460

Let the age of eldest child is E , that of elder child is M and that of youngest child is Y, then according to the given conditions

E = 3Y  (1) and  E = 2 + M + Y  (2)

Third condition is somewhat complicated, according to this condition two of the age difference is 3 so three cases will arise 

1) E - M = 3, ......(3)

2) M - Y = 3, ......(4)

3) E - Y = 3, ......(5)

if we take first of the 3 conditions then on solving (1), (2) and (3) we will get E = 3, M = 0, Y = 1 which is wrong now on solving (1), (2) and (4) we will get E = 15, M = 8, Y = 5

similarity on solving (1), (2) and (5) we will get E = 4.5, M = 1, Y = 1.5

only E = 15, M = 8, Y = 5 is correct so age of elder child is 8 years.

FEB. 14, 2005   IS A  MONDAY

From Feb. 14, 2005 to Feb. 14 2006, there will be 365 days which means one odd day. 

So, FEB. 14, 2006   WILL BE A  TUESDAY

From Feb. 14, 2006 to Feb. 14 2007, there will be 365 days which means one odd day. 

So, FEB. 14, 2007   WILL BE A  WEDNESDAY 

From Feb. 14, 2007 to Feb. 14 2008, there will be 365 days which means one odd day. 

So, FEB. 14, 2008   WILL BE A  THURSDAY 

From Feb. 14, 2008 to Feb. 14 2009, there will be 366 days

- add one more odd day for Feb.2@Total is 2 odd days. 

So FEB. 14, 2009    WILL BE A  SATURDAY

From Feb. 14, 2009 to Feb. 14 2010, there will be 365 days

one  odd day . 

So FEB. 14, 2010    WILL BE A  SUNDAY

Tank B is filled in geometric progression, so after 22 hrs water in tank will be = 10 * 2^21 = x/8 

where x = volume of tank x = 10 * 2^24 thus by geometric progression we get that n-1 = 24 

so n = 25, hence time required is  25 hrs.

Left and right consecutive movement nullified the change in direction. So, he is in the direction he started with. 

Let the age of two friends be 6x and 5x

Sum of their ages 66 => 6x + 5x = 66 => 11x = 66 => x=6

The ages will be 36 and 30

 (36+k)/(30+k) = 7/6 => 36 x 6 + 6k = 210 + 7k

216 + 6k = 210 + 7k => 6 = k

After 6 years their ages will be in the ratio 7:6