Explanation:
by ohms law
v = ir
so r = v/i
so r = 80/20 = 4
The Answer is 2@First he will select 24 in that the maximum chance is all are red so if we take one more socks, it has to be the other color. Hence, the answer is 24 + 1 = 25
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) =n(E)/n(S)=9/20
No of ways of selecting 2 from hotel (6 choices) = 6C2
And from home (2 choices) = 2C2
2C2 x 6C2 = 1 x 15 = 15 ways
One number be x and other y, then x - y = 9
(x - y)2 = 81
x2 + y2 = 81 + 2xy = 109
(x+y)2 = x2 + y2 + 2xy = 109 + 28 = 137
So answer is 137
a: b = 3:5
b: c = 8: 5
a:b:c = 24 : 40 : 25 and total is 24+40+25 = 89
(40/89) x 35 = 15.73
(3/4)t=1
t=4/3=1+1/3
She will have to increase her speed by 33.333% to run the same distance in 3/4s of the time
1= 5^4-1=125, n= no of digits
1 2
2 4
3 2
4 4
5 2
The first two digits in the place can be filled in 5 x 5 ways.
So there are totally 25 x 5 = 125 ways
Have 6 mice for testing,
Give each mice contents from 5 cans each
5 5 5 5 5 5
After 14 hours, one of the mice will die
So, we will know which 5 cans must have the poison
Then , take the contents of these 5 cans and give to the remaining 5 mice each.
We will know in due time which can is poisoned
5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30
Let the age be the friends be 2x and 3x. Sum of their ages = 55
2x + 3x = 55 => 5x=55 => x=11
Their ages are 22 and 33
After k years both of them will be 22+k and 33+k years old
Ratio of their age at that time will me 4:5
(22+k)/(33+k)=4/5
5(22+k)=4(33+4) => 110 + 5k = 132+4k
K=132-110 = 22
Distance between the starting and end point is 37 + 17 = 54.
Probability for the bacteria to be dying = 1/3
Hence probability of survival = 1/5
if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5)
12 x 11 / 2 = 66 Handshakes.
Probability of bacteria to die is 1/3
or its get tripled, hence the probability of getting tripled is (2/3)*p*p*p that is (2/3)*p^3
so both the probability combined as P=1/3+(2/3*p^3)
Let the capacity of the tank be 6 litre.
Then time to fill this tank is 6 hour ,when there is no leakage .
so in 1 hour it fills 1 litre.
when leakage is there then it takes 6.5 hour to fill 6 litre
so in 1 hour it fills 6/6.5 litre.
Time to vacate will be 1-(6/6.5) = 1/13 litre in 1 hour
time to vacate 1 litre will be 13 hour.
For 6 litre it will be 13*6 =78
Area = 20 x 30 = 600 cm^2
Bricks = 600 x 35 = 21000
Speed = 54 x5/18 m/sec = 15 m/sec.
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then,x + 300/36 = 15
x + 300 = 540
x = 240 m.
Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = (68/17)hrs = 4 hrs.
Dimensions = 4 x 5 x 2
TSA = 2 (4 x 5 + 5 x 2 + 4 x 2) = 2(20+10+8)=2x38 = 76 sq m
So bricks required = 76 x 17 = 1292
For 5 rooms 1292 x5 = 6460
Let the age of eldest child is E , that of elder child is M and that of youngest child is Y, then according to the given conditions
E = 3Y (1) and E = 2 + M + Y (2)
Third condition is somewhat complicated, according to this condition two of the age difference is 3 so three cases will arise
1) E - M = 3, ......(3)
2) M - Y = 3, ......(4)
3) E - Y = 3, ......(5)
if we take first of the 3 conditions then on solving (1), (2) and (3) we will get E = 3, M = 0, Y = 1 which is wrong now on solving (1), (2) and (4) we will get E = 15, M = 8, Y = 5
similarity on solving (1), (2) and (5) we will get E = 4.5, M = 1, Y = 1.5
only E = 15, M = 8, Y = 5 is correct so age of elder child is 8 years.
Mohans speed = 35 Km/hr
Rohit speed = 4 x Mohan speed = 4 x 35 = 140 Kmph
Time taken =Distance / Speed = 490 / 140 = 49/14 = 7/2
FEB. 14, 2005 IS A MONDAY
From Feb. 14, 2005 to Feb. 14 2006, there will be 365 days which means one odd day.
So, FEB. 14, 2006 WILL BE A TUESDAY
From Feb. 14, 2006 to Feb. 14 2007, there will be 365 days which means one odd day.
So, FEB. 14, 2007 WILL BE A WEDNESDAY
From Feb. 14, 2007 to Feb. 14 2008, there will be 365 days which means one odd day.
So, FEB. 14, 2008 WILL BE A THURSDAY
From Feb. 14, 2008 to Feb. 14 2009, there will be 366 days
- add one more odd day for Feb.2@Total is 2 odd days.
So FEB. 14, 2009 WILL BE A SATURDAY
From Feb. 14, 2009 to Feb. 14 2010, there will be 365 days
one odd day .
So FEB. 14, 2010 WILL BE A SUNDAY
d = 4*(t-9)
Given r = 12 mm
So, d = 24 mm
So,
24 = 4t - 36
4t = 60
t = 15 years
Tank B is filled in geometric progression, so after 22 hrs water in tank will be = 10 * 2^21 = x/8
where x = volume of tank x = 10 * 2^24 thus by geometric progression we get that n-1 = 24
so n = 25, hence time required is 25 hrs.
Left and right consecutive movement nullified the change in direction. So, he is in the direction he started with.
Horse covers = 81*3 = 243 kms
So ponies speed = 243/(2+3) = 243/5 = 48.6
Let the age of two friends be 6x and 5x
Sum of their ages 66 => 6x + 5x = 66 => 11x = 66 => x=6
The ages will be 36 and 30
(36+k)/(30+k) = 7/6 => 36 x 6 + 6k = 210 + 7k
216 + 6k = 210 + 7k => 6 = k
After 6 years their ages will be in the ratio 7:6