1C1*1C(N-1)*1C(N-2)/3C(N-3)

100-20%=80% ; 80-20%=64 ; 64-20%= 51.2%

But less than 14 also possible so goes through the option.

3

Divide the 7p into 1p, 2p, and 4p.

1p = 1p

2p = 2p

3p = 1p + 2p

4p = 4p

5p = 4p + 1p

6p = 4p + 2p

7p = 4p + 2p + 1p

our number is xy9

now if x is 0 then y has 10 options

now if x is 1 then y has 9 options (except 9)

now if x is 2 then y has 8 options (except 9 and 8)

.

.

.

now if x is 9 then y has 1 option (that is 0)

**No it must be 16**

Since H+D=22

T+D=23

ALL=15

then 76=22+23+15+(H+T)

H+T=76-60=16.

at 39th min it will b back at 57meters and again at 40th min it will be back at 60meters.

**Ans: 3**

When the number is divided by 3D we got 2@Me the number itself is 21 and 3D >21.

when 21/D, remainder is 8.

So D = 21-8 =13.

now (21*2)/(13*3), Remainder is 3.

**The is 4AM.**

The distance among their is (60+60)=120,

4*120=480...

THEN V HAV TO CONVERT HRS..480/60=8HRS

10-8=2HRS

IT STARTS 2AM SO 2+2=4AM.

4.5 kms

54 kilometers per hours = 54000 meters per hour

54000 meters / 60 minutes = 900 meters per minute

900 meters * 5 minutes of traveling time = 4500 meters travel

4500 meters = 4.5 kilometers traveled in 5 minutes

If A=0 And B=1 then both equation are satisfied....

(8, 1000) (2^3, 10^3)

(4, 100) (2^ 2, 10^2)

(1,1)( 2^0, 10^0)

(2,?)( 2^1, 10^1)

car/2wheeler=1/8,suppose car be X & 2wheeler be Y.

X/Y=1/8; Y=8X also there r 4 tyre in 1 car & 2 tyre in 1 two wheeler ;

therefore 4X + 2Y=100

Solving these 2 eq. X=5 & Y=40.

=(5/6)*(6/7)*(7/8)*...((n+3)/(n+4))*((n+4)/(n+5))

=5/n+5

The formula for this question is M1*D1*W2=M2*D2*W1.

So putting all these values we get the wer to be 12 minutes.

= 25

bcoz, 3*3=9

3*6=18

3*7=21

5*5=25

5*4=20

so like(3*6 and 3*7 it will be 5*4 and 5*5 mens increment by 1)

**440s**

Let velocity of A,B and C be a,b,c resp.

2(pi)r/88 = a+c

2(pi)r/110 = b+c

we have to find 2(pi)r/a-b

**Ans: 440**

among 3 socks she has to choose 2 black socks from 9 pair(=18) of black socks, that can be done in 18C2 ways. and the third sock can be chosen from among the remaining socks that can be done in ((8+9-1)x2 )C 1 ways i.e. in 32 ways.

**.** 32 X 18C2.

declare

-- Local variables here

i integer;

begin

-- Test statements here

for i in 1..99919 loop

if mod(99919,i) = 0 then

dbms_output.put_line (i);

end if;

end loop;

end;

**If you paint the cube such that:**

- Blue and Blue are on opposite sides
- Red and Red are on opposite side
- Yellow and Yellow are on opposite side
- And, since the question didnt state where the 32 smaller could be, Im placing the 32 smaller cubes on the sides with Blue paint.
- Thus: 32 cubes have Blue on at least one side.
- 20 cubes have have colors on two sides.

The 4cm cube is divide into 125 smaller cubes:

that me that the 4cm cube = 5 smaller cubes in height, width, and depth

Also, given that the 4cm is painted red on all six side:

- only those smaller cubes that touch no outer surface will be free of red paint,
- 27 smaller cubes have no red paint on them.
- 98 smaller cubes have some red paint on them.

1/3+1/5+1/x=1/8

**solution:**

1/3+1/5-1/8=1/x

40+24-15 =1/x

120

49/120=1/x

x=120/49

or

x=2 22/49 in fraction

4/5 full tank= 12 miles.

1 full tank= 12/(4/5).

1/3 full tank= 12/(4/5)*(1/3)= 5 miles.

(log a + log b)(log a- log b) =log ab . log a/b

300 in the nigiets base 8

192 in the base 10 for us ....

The wer is total of **192 (base 10)**

245 pieces have no color on them,98 pieces have black on one side.

Train crossed the car with less speed in less time and the car with high speed in more time.i.e train and two cars going in the same direction.

hence 1st car

L/((S-45)*5/18)=36 i.e L=10S-450

similarly for 2nd car

L=15S-750

BY solving these two equations we get length of the train L=150mtrs

** -160**

jus suppose 1st plan all paid x rs me individually x/4

2nd plan

x eqals= 240+x/4+x/4+x/8

solving x equals 640

so

paid by B is x/4

160

Exactly 24 days...

1 man do 1/44 job per day.

2 woman do 1/44 job per day.

3 children do 1/44 job per day.

so

1man , 1 woman , 1 child.

1/44+1/88+1/132 job per day

so 11/264 = 1/t where t is the time taken.

now 264/11 = 24 = t

only those smaller cubes that do not touch the edges of the 4cm cube will have only one side painted, thus:

- 54 smaller cubes have only one side painted

- 36 smaller cubes have two sides painted

- 8 smaller cubes have three sides painted

A,E,I,O,U is the Answer.