Intuit Aptitude Placement Papers - Intuit Aptitude Interview Questions and Answers updated on 19.Mar.2024

30 * 25 = 750

                425

             -----------

                 325

25 + 7.50 = 32.5

325/32.5 = 10.

[(523 + 27) * (187 - 35) / (424 + 16)] / [110/22 of (2 * 38)] 

= [(550 * 152) / 440] / [(110/44) * 38]

= (5 * 38)/(5/2 * 38) = 2.

Speed downstream = (5+1)km/hr = 6 km/hr

Speed upstream = (5-1)km/hr = 4 km/hr 

Let the required distance be x km. 

Then x/6 + x/4 = 75/60 = 5/4 => (2x + 3x) =15 => x =3. 

Required distance = 3 km.

Speed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3 

3(x + 300) = 1950 è x = 350m.

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 ----- (1)

(10Q + P) - (10P + Q) = 54

9(Q - P) = 54

(Q - P) = 6 ----- (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28

A scores 60 while B score 40 and C scores 30.

The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.

In a game of 100 points, B gives (100 - 75) = 25 points to C.

25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 =  1/100 * x => x = 25000.

If both agree stating the same fact, either both of them speak truth of both speak false.

Probability = 3/5 * 4/7 + 2/5 * 3/7

= 12/35 + 6/35 = 18/35.

Let the five consecutive odd numbers of set p be 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.

Sum of these five numbers

= 2n - 3 + 2n - 1 + 2n + 1 + 2n + 3 + 2n + 5

= 10n + 5 = 435 => n = 43

Largest number of set p = 2(43) + 5 = 91

The largest number of set q = 91 + 45 = 136

=> The five numbers of set q are 132, 133, 134, 135, 136.

Sum of above numbers = 132 + 133 + 134 + 135 + 136 = 670.

The fractions considered are 8/15 9/13 6/11

To compare them we make the denominators the same. So the fractions are

(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145

1144/2145, 1485/2145 and 1170/2145

so in descending order the fractions will be 

1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15.

Let the required percentage be x%.

3/20 = x% of 12/25 => 3/20 = x/100 * 12/25

=> 12x = (300 * 25)/20 => x = (25 * 25)/20

=> x = 31.25%.

The circumference of the circle is equal to the permeter of the rectangle. 

Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5 

 =>  x = 1 

Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2.

2x2 + 6x - 3x - 9 = 0

2x(x + 3) - 3(x + 3) = 0

(x + 3)(2x - 3) = 0

=> x = -3 or x = 3/2.

Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]

= [1600 * 41/40(41/40 + 1) 

= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.

C.I. = 3321 - 3200 = Rs. 121.

Three consecutive numbers can be taken as (P - 1), P, (P + 1).

So, (P - 1) + P + (P + 1) = 102

3P = 102 => P = 34.

The lowest of the three = (P - 1) = 34 - 1 = 33.

Area of the four walls = 2h(l + b)

Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.

Total cost = 906 * 5 = Rs. 4530.

Let the length of the train be x meters and its speed be y m/sec.

They, x / y = 15 => y = x/15 

x + 100 / 25 = x / 15 

 x = 150 m. 

The ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph.

1/2:1/3:1/4 = 6:4:3

Ram = 6/13 * 3250 = 1500

Shyam = 4/13 * 3250 = 1000

Mohan = 3/13 * 3250 = 750.

Let the amount with R be Rs.r

r = 2/3 (total amount with P and Q)

r = 2/3(6000 - r) => 3r = 12000 - 2r

=> 5r = 12000 => r = 2400.

A + B = 60, A = 2B

2B + B = 60 => B = 20 then A = 40.

5 years, their ages will be 45 and 25.

Sum of their ages = 45 + 25 = 70.

1860 + 4/7 of 21.21 - 41.4 = 1860 + 4(3.03) - 41.4

= 1860 + 12.12 - 41.4 = 1872.12 - 41.4

= 1830.72.

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm2.

Let x percent of 80 be 64.

80 * x/100 = 64 => x = (64 * 100)/80 => x = 80.

80% of 80 is 64.

Length = 6x 

Breadth = 5x 

Height = 4x in cm 

Therefore, 2(6x × 5x + 5x × 4x + 6x × 4x) = 33300 

148x2 = 33300 

=> x2 = 33300/148 = 225 

=> x = 15. 

Therefore, Length = 90cm, 

Breadth = 75cm, 

Height = 60cm 

90, 75 , 60 cm.

Let the numerator and denominator of the fraction be 'n' and 'd' respectively.

d = 2n - 1

(n + 1)/(d + 1) = 3/5

5n + 5 = 3d + 3

5n + 5 = 3(2n - 1) + 3 => n = 5

d = 2n - 1 => d = 9

Hence the fraction is : 5/9.

2C + 3T = 1300 --- (1)

3C + 3T = 1200 --- (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T - C = 100.

2x.....3x

8x cube + 27x cube = 945

35x cube = 945

x cube = 27 => x = 3.

1 to 11 = 11 * 10.9 = 119.9

1 to 6 = 6 * 10.5 = 63

6 to 11 = 6 * 11.4 = 68.4

63 + 68.4 = 131.4 – 119.9 = 11.5

6th number = 11.5.

1/4 + 1/5 = 9/20

 20/9 = 2 2/9

 9/20 * 2 = 9/10 ---- 4 hours

 WR = 1 - 9/10 = 1/10

 1 h ---- 1/4

 ? ----- 1/10

 2/5 * 60 = 24 = 4 hrs 24 min.