Q1. A Can Do A Piece Of Work In 12 Days. He Worked For 15 Days And Then B Completed The Remaining Work In 10 Days. Both Of Them Together Will Finish It In?

15/25 + 10/x = 1 => x = 25

1/25 + 1/25 = 2/25

25/2 = 12 1/2 days.

Q2. A Laborer Is Engaged For 30 Days On The Condition That He Receives Rs.25 For Each Day He Works And Is Fined Rs.7.50 For Each Day Is Absent. He Gets Rs.425 In All. For How Many Days Was He Absent?

30 * 25 = 750

425

-----------

325

25 + 7.50 = 32.5

325/32.5 = 10.

Q3. [(523 + 27) * (187 - 35) / (424 + 16)] / [110/22 Of (2 * 38)] = ?

[(523 + 27) * (187 - 35) / (424 + 16)] / [110/22 of (2 * 38)]

= [(550 * 152) / 440] / [(110/44) * 38]

= (5 * 38)/(5/2 * 38) = 2.

Q4. A Man Can Row At 5 Km/hr In Still Water, If The River Is Running At 1 Km/hr It Takes Him 75 Minutes To Row To A Place And Back. How Far Is The Place?

Speed downstream = (5+1)km/hr = 6 km/hr

Speed upstream = (5-1)km/hr = 4 km/hr

Let the required distance be x km.

Then x/6 + x/4 = 75/60 = 5/4 => (2x + 3x) =15 => x =3.

Required distance = 3 km.

Q5. Rs.1170 Is Divided So That 4 Times The First Share, Thrice The 2nd Share And Twice The Third Share Amount To The Same. What Is The Value Of The Third Share?

A+B+C = 1170

4A = 3B = 2C = x

A:B:C = 1/4:1/3:1/2 = 3:4:6

6/13 * 1170 = Rs.540.

Q6. A 300 Meter Long Train Crosses A Platform In 39 Seconds While It Crosses A Signal Pole In 18 Seconds. What Is The Length Of The Platform?

Speed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 è x = 350m.

Q7. The Radius Of A Cylindrical Vessel Is 7cm And Height Is 3cm. Find The Whole Surface Of The Cylinder?

r = 7 h = 3

2πr(h + r) = 2 * 22/7 * 7(10) = 440.

Q8. The Sum Of The Two Digits Of A Number Is

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 ----- (1)

(10Q + P) - (10P + Q) = 54

9(Q - P) = 54

(Q - P) = 6 ----- (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28

Q9. In A Game Of Billiards, A Can Give B 20 Points In 60 And He Can Give C 30 Points In 6

A scores 60 while B score 40 and C scores 30.

The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.

In a game of 100 points, B gives (100 - 75) = 25 points to C.

Q10. A Brick Measures 20 Cm * 10 Cm * 7.5 Cm How Many Bricks Will Be Required For A Wall 25 M * 2 M * 0.75 M?

25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000.

Q11. The Probability That A Speaks Truth Is 3/5 And That Of B Speaking Truth Is 4/

If both agree stating the same fact, either both of them speak truth of both speak false.

Probability = 3/5 * 4/7 + 2/5 * 3/7

= 12/35 + 6/35 = 18/35.

Q12. The Sum Of Five Consecutive Odd Numbers Of Set P Is 43

Let the five consecutive odd numbers of set p be 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.

Sum of these five numbers

= 2n - 3 + 2n - 1 + 2n + 1 + 2n + 3 + 2n + 5

= 10n + 5 = 435 => n = 43

Largest number of set p = 2(43) + 5 = 91

The largest number of set q = 91 + 45 = 136

=> The five numbers of set q are 132, 133, 134, 135, 136.

Sum of above numbers = 132 + 133 + 134 + 135 + 136 = 670.

Q13. A Train Crosses A Platform Of 120 M In 15 Sec, Same Train Crosses Another Platform Of Length 180 M In 18 Sec. Then Find The Length Of The Train?

Length of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180m .

Q14. Which Of The Following Groups Of Fractions Is In Descending Order?

The fractions considered are 8/15 9/13 6/11

To compare them we make the denominators the same. So the fractions are

(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145

1144/2145, 1485/2145 and 1170/2145

so in descending order the fractions will be

1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15.

Q15. There Were Two Candidates In An Election. Winner Candidate Received 62% Of Votes And Won The Election By 288 Votes. Find The Number Of Votes Casted To The Winning Candidate?

W = 62% L = 38%

62% - 38% = 24%

24% -------- 288

62% -------- ? => 744.

Q16. Sides Of A Rectangular Park Are In The Ratio 3: 2 And Its Area Is 3750 Sq M, The Cost Of Fencing It At 50 Ps Per Meter Is?

3x * 2x = 3750 => x = 25

2(75 + 50) = 250 m

250 * 1/2 = Rs.125.

Q17. A Rectangular Field Has Area Equal To 150 Sq M And Perimeter 50 M. Its Length And Breadth Must Be?

2(l + b) = 50 => l + b = 25

l – b = 5

l = 15 b = 10.

Q18. 3/20 Is What Percent Of 12/25?

Let the required percentage be x%.

3/20 = x% of 12/25 => 3/20 = x/100 * 12/25

=> 12x = (300 * 25)/20 => x = (25 * 25)/20

=> x = 31.25%.

Q19. How Many Minimum Number's Of Whole Square Slabs Are Required For Paving The Floor 12.96 Meters Long And 3.84 Meters Side?

HCF of 384, 1296 = 48

48 * 48 * x = 384 * 1296

x = 216.

Q20. A Wire In The Form Of A Circle Of Radius 3.5 M Is Bent In The Form Of A Rectangule, Whose Length And Breadth Are In The Ratio Of 6 :

The circumference of the circle is equal to the permeter of the rectangle.

Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5

=> x = 1

Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2.

Q21. Find The Roots Of The Quadratic Equation: 2x^{2} + 3x - 9 = 0?

2x^{2} + 6x - 3x - 9 = 0

2x(x + 3) - 3(x + 3) = 0

(x + 3)(2x - 3) = 0

=> x = -3 or x = 3/2.

Q22. A Bank Offers 5% C.i. Calculated On Half-yearly Basis . A Customer Deposits Rs. 1600 Each On 1st January And 1st July Of A Year. At The End Of The Year, The Amount He Would Have Gained By Way Of Inter

Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]

= [1600 * 41/40(41/40 + 1)

= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.

C.I. = 3321 - 3200 = Rs. 121.

Q23. The Sum Of Three Consecutive Integers Is

Three consecutive numbers can be taken as (P - 1), P, (P + 1).

So, (P - 1) + P + (P + 1) = 102

3P = 102 => P = 34.

The lowest of the three = (P - 1) = 34 - 1 = 33.

Q24. Two Pipes Can Separately Fill A Tank In 20 And 30 Hours Respectively. Both The Pipes Are Opened To Fill The Tank But When The Tank Is Full, A Leak Develops In The Tank Through Which One-third Of W

1/20 + 1/30 = 1/12

1 + 1/3 = 4/3

1 --- 12

4/3 --- ?

4/3 * 12 = 16 hrs.

Q25. A Room Is 4 Meters 37 Cm Long And 3 Meters 23cm Broad. It Is Required To Pave The Floor With Minimum Square Slabs. Find The Number Of Slabs Required For This Purpose?

HCF of 323, 437 = 19

323 * 437 = 19 * 19 * x

x = 391.

Q26. The Equal Amounts Of Money Are Deposited In Two Banks Each At 15% Per Annum For 3.5 Years And 5 Years Respectively. If The Difference Between Their Interests Is Rs.144, Find The Each Sum?

(P*5*15)/100 - (P*3.5*15)/100 = 144

75P/100 – 52.5P/100 = 144

22.5P = 144 * 100

=> P = Rs.640.

Q27. The Dimensions Of A Room Are 25 Feet * 15 Feet * 12 Feet. What Is The Cost Of White Washing The Four Walls Of The Room At Rs. 5 Per Square Feet If There Is One Door Of Dimensions 6 Feet * 3 Feet And T

Area of the four walls = 2h(l + b)

Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.

Total cost = 906 * 5 = Rs. 4530.

Q28. A Train Speeds Past A Pole In 15 Seconds And A Platform 100 M Long In 25 Seconds. Its Length Is?

Let the length of the train be x meters and its speed be y m/sec.

They, x / y = 15 => y = x/15

x + 100 / 25 = x / 15

x = 150 m.

Q29. The Time Taken By A Man To Row His Boat Upstream Is Twice The Time Taken By Him To Row The Same Distance Downstream. If The Speed Of The Boat In Still Water Is 42 Kmph, Find The Speed Of The Stream?

The ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph.

Q30. If Rs.3250 Be Divided Among Ram, Shyam And Mohan In The Ratio Of 1/2:1/3:1/4 Then The Share Of Each Are?

1/2:1/3:1/4 = 6:4:3

Ram = 6/13 * 3250 = 1500

Shyam = 4/13 * 3250 = 1000

Mohan = 3/13 * 3250 = 750.

Q31. 4000 Was Divided Into Two Parts Such A Way That When First Part Was Invested At 3% And The Second At 5%, The Whole Annual Interest From Both The Investments Is?

(x*3*1)/100 + [(4000 - x)*5*1]/100 = 144

3x/100 + 200 – 5x/100 = 144

2x/100 = 56 è x = 2800.

Q32. Two Cars Cover The Same Distance At The Speed Of 60 And 64 Kmps Respectively. Find The Distance Traveled By Them If The Slower Car Takes 1 Hour More Than The Faster Car?

60(x + 1) = 64x

X = 15

60 * 16 = 960 km.

Q33. The Tax On A Commodity Is Diminished By 20% But Its Consumption Is Increased By 10%. Find The Decrease Percent In The Revenue Derived From It?

100 * 100 = 10000

80 * 110 = 8800

10000------- 1200

100 ------- ? = 12%.

Q34. Two Trains Each 250 M In Length Are Running On The Same Parallel Lines In Opposite Directions With The Speed Of 80 Kmph And 70 Kmph Respectively. In What Time Will They Cross Each Other Completely?

D = 250 m + 250 m = 500 m

RS = 80 + 70 = 150 * 5/18 = 125/3

T = 500 * 3/125 = 12 sec.

Q35. P, Q And R Have Rs.6000 Among Themselves. R Has Two-thirds Of The Total Amount With P And Q. Find The Amount With R?

Let the amount with R be Rs.r

r = 2/3 (total amount with P and Q)

r = 2/3(6000 - r) => 3r = 12000 - 2r

=> 5r = 12000 => r = 2400.

Q36. How Many Seconds Will A Train 100 Meters Long Take To Cross A Bridge 150 Meters Long If The Speed Of The Train Is 36 Kmph?

D = 100 + 150 = 250

S = 36 * 5/18 = 10 mps

T = 250/10 = 25 sec.

Q37. The Sum Of The Present Ages Of Two Persons A And B Is 6

A + B = 60, A = 2B

2B + B = 60 => B = 20 then A = 40.

5 years, their ages will be 45 and 25.

Sum of their ages = 45 + 25 = 70.

Q38. 1860 + 4/7 Of 21.21 - 41.4 = ?

1860 + 4/7 of 21.21 - 41.4 = 1860 + 4(3.03) - 41.4

= 1860 + 12.12 - 41.4 = 1872.12 - 41.4

= 1830.72.

Q39. If The Sides Of A Triangle Are 26 Cm, 24 Cm And 10 Cm, What Is Its Area?

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2}.

Q40. 64 Is What Percent Of 80?

Let x percent of 80 be 64.

80 * x/100 = 64 => x = (64 * 100)/80 => x = 80.

80% of 80 is 64.

Q41. If The Length, Breadth And The Height Of A Cuboid Are In The Ratio 6: 5: 4 And If The Total Surface Area Is 33300 Cm2, Then Length Breadth And Height In Cms, Are Respectively?

Length = 6x

Breadth = 5x

Height = 4x in cm

Therefore, 2(6x × 5x + 5x × 4x + 6x × 4x) = 33300

148x2 = 33300

=> x2 = 33300/148 = 225

=> x = 15.

Therefore, Length = 90cm,

Breadth = 75cm,

Height = 60cm

90, 75 , 60 cm.

Q42. The Denominator Of A Fraction Is 1 Less Than Twice The Numerator. If The Numerator And Denominator Are Both Increased By 1, The Fraction Becomes 3/

Let the numerator and denominator of the fraction be 'n' and 'd' respectively.

d = 2n - 1

(n + 1)/(d + 1) = 3/5

5n + 5 = 3d + 3

5n + 5 = 3(2n - 1) + 3 => n = 5

d = 2n - 1 => d = 9

Hence the fraction is : 5/9.

Q43. The Cost Of 2 Chairs And 3 Tables Is Rs.13

2C + 3T = 1300 --- (1)

3C + 3T = 1200 --- (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T - C = 100.

Q44. A Property Decreases In Value Every Year At The Rate Of 6 1/4% Of Its Value At The Beginning Of The Year Its Value At The End Of 3 Years Was Rs.2109

6 1/4% = 1/16

x *15/16 * 15/16 * 15/16 = 21093

x = 25600.24.

Q45. The Ratio Of Two Numbers Is 2:3 And The Sum Of Their Cubes Is 94

2x.....3x

8x cube + 27x cube = 945

35x cube = 945

x cube = 27 => x = 3.

Q46. The Average Of 11 Numbers Is 10.

1 to 11 = 11 * 10.9 = 119.9

1 to 6 = 6 * 10.5 = 63

6 to 11 = 6 * 11.4 = 68.4

63 + 68.4 = 131.4 – 119.9 = 11.5

6th number = 11.5.

Q47. A Is Thrice As Efficient As B And Is, Therefore, Able To Finish A Piece Of Work 10 Days Earlier Than B. In How Many Days A And B Will Finish It Together?

WC = 3:1

WT = 1:3

x ............3x

1/x – 1/3x = 1/10

x = 20/3

3/20 + 1/20 = 1/5 => 5 days.

Q48. A Can Do A Piece Of Work In 30 Days. He Works At It For 5 Days And Then B Finishes It In 20 Days. In What Time Can A And B Together It?

5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 days.

Q49. A, B And C Are Entered Into A Partnership. A Invested Rs.6500 For 6 Months, B Invested Rs.8400 For 5 Months And C Invested For Rs.10000 For 3 Months. A Is A Working Partner And Gets 5% Of The Total Pr

65 * 6 : 84 * 5 : 100 * 3

26:28:20

C share = 74000 * 95/100 = 7030 * 20/74 => 1900.

Q50. Two Pipes A And B Can Fill A Tank In 4 And 5 Hours Respectively. If They Are Turned Up Alternately For One Hour Each, The Time Taken To Fill The Tank Is?

1/4 + 1/5 = 9/20

20/9 = 2 2/9

9/20 * 2 = 9/10 ---- 4 hours

WR = 1 - 9/10 = 1/10

1 h ---- 1/4

? ----- 1/10

2/5 * 60 = 24 = 4 hrs 24 min.