Impetus Aptitude Placement Papers - Impetus Aptitude Interview Questions and Answers updated on 23.Jul.2024

Q1. Mahesh And Umesh Can Complete A Work In 10 Days And 15 Days Respectively. Umesh Starts The Work And After 5 Days Mahesh Also Joins Him In All The Work Would Be Completed In?

Umesh’s 5 day’s work = 5 x 1/15 = 1/3 

Remaining work = (1 – 1/3) = 2/3 (1/10 +1/ 15) work is done by both in 1 day 

Therefore 2/3 work is done by both in (6 x 2/3) = 4days. 

The work was completed in 9 days.

Q2. In Covering Distance, The Speed Of A & B Are In The Ratio Of 3:4.a Takes 30min More Than B To Reach The Destination. The Time Taken By A To Reach The Destination Is?

Ratio of speed = 3:4

Ratio of time = 4:3

let A takes 4x hrs, B takes 3x hrs

then 4x-3x = 30/60 hr

x = ½ hr

Time taken by A to reach the destination is 4x = 4 * ½ = 2 hr.

Q3. A Person Invests Money In Three Different Schemes For 6 Years, 10 Years And 12 Years At 10 %, 12 %, And 15 %. Simple Interest Respectively. At The Completion Of Each Scheme, He Gets The Same Interest.

Let the required ratio be x: 1: y. 

Then S.I on Rs x for 6 years at 10% p.a = S.I on re.1 10 years at 12 %p.a 

X × 10/100 × 6 = 1 × 12/100 × 10 

=> X = 120/60 =2 

S.I on Re.1 for 10 years at 12 % p.a = S. I on Rs. Y for 12 years at 15 % p.a 

Therefore, (1 x 12/100 x 10) = (y x 15/100 x 12) 

=> y = 120/180 = 2/3 

Required ratio = 2 : 1 = 2/3 = 6 : 3 : 2.

Q4. Twelve Men Can Complete A Work In 8 Days. Three Days After They Started The Work, 3 More Men Joined Them. In How Many Days Will All Of Them Together Complete Remaining Work?

1 man’s one day’s work = 1/96 12 men’s 3 day’s work = (3 x 1/8) = 3/8 

Remaining work = (1 – 3/8) = 5/8 15 men’s 1 day’s work = 15/96 

Now 15/96 work is done by them in 1day 

Therefore 5/8 work will be done by them in (96/15 x 5/8) i.e., 4 days.

Q5. A Borrows Rs.800 At The Rate Of 12 % Per Annum. Simple Interest And B Borrows Rs.910 At The Rate Of 10 % Per Annum Simple Interest. In How Many Years Will Their Amounts At Debts Be Equal?

Let the required time be x years. 

Then 800 + 800 x 12/100 × x = 910 + 910 x 10/100 × x 

=> (96x -91 x) = 110 

=> 5x =110 

=> x =22.

Q6. A Discount Series Of 10%, 20% And 40% Is Equal To A Single Discount Of?

Original price = Rs. 100 

Price after first discount = Rs. 90 

Price after second discount = Rs. (80/100 × 90) = Rs. 72 

Price after third discount = Rs. (60/100 × 72) = Rs. 43.20 

Single discount = (100 – 43.20) = 56.8%.

Q7. If Rs. 510 Be Divided Among A, B, C In Such A Way That A Gets 2/3 Of What B Gets And B Gets 1/4 Of What C Gets, Then Their Shares Are Respectively?

(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4

A:B = 2:3 and B:C = 1:4 = 3:12

A:B:C = 2:3:12

A;s share = 510 * 2/17 = Rs. 60

B's share = 510 * 3/17 = Rs. 90

C's share = 510 * 12/17 = Rs. 360.

Q8. If The Interest Is Payable Annually Than The Principal On Which The Compound Interest For 3 Years At 10% P.a Is Rs 33/- Is Given By?

Let the principal be Rs x. 

Then X × (1 + 10/100)3 – x = 331 

=> (x × 11/10 × 11/10 × 11/10 - x) = 331

=> ((1331x-1000x)/1000) = 331 

=> 331x = 331000 

=> X = 1000 

Hence the principal is Rs 1000.

Q9. X Varies Inversely As Square Of Y. Given That Y = 2 For X =

Given x = k/y2, where k is a constant. 

Now, y = 2 and x = 1 gives k = 4. 

x = 4/y2 => x = 4/62, when 

y = 6 => x = 4/36 = 1/9.

Q10. Megha Purchased 120 Calendars At A Rate Of Rs 3 Each And Sold 1/3 Of Them At The Rate Of Rs. 4 Each. 1/2 Of Them At The Rate Of Rs 5 Each And Rest At The Cost Price. Her Profit Per Cent Was?

CP of 120 calendars = 120 x 3 = Rs. 360

SP of 40 at Rs. 4 each = Rs. 40 x 4 = Rs.160

SP of 60 at Rs 5 each = Rs 60 x 5 = Rs. 300

SP of remaining 20 calendars = Rs 20 x 3 = 60

Total SP = Rs.( 160 + 300 + 60) = 520

Profit % = 520 – 360 = 160

Profit % = 160/360 x 100 = 400/9.

Q11. A Certain Distance Covered At A Certain Speed. If Half Of This Distance Is Covered In Double The Time The Ratio Of The Two Speeds Is?

Let x kms be covered in y hours, then first speed = x / y km/hr

Again x/2 km is covered in 2y hrs 

Therefore, new speed = (x/2 x 1/2y)km/hr 

= (x/ 4y) km/hr 

Ratio of speeds = x/y : x/4y = 1 : ¼

= 4 : 1.

Q12. A Tank Is Filled In 5 Hours By Three Pipes A, B And C. The Pipe C Is Twice As Fast As B And B Is Twice As Fast As A. How Much Time Will Pipe A Alone Take To Fill The Tank?

Suppose pipe A alone takes x hours to fill the tank.

Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.

1/x + 2/x + 4/x = 1/5

7/x = 1/5 => x = 35 hrs.

Q13. Two Trains Approach Each Other At 30 Km/hr And 27km/hr From Two Places 342km Apart After How Many Hours Will They Meet?

Suppose the two trains meet after x hours, then 

=> 30x + 27x = 342 

=> 57x = 342 

=> X = 6 

So the two trains will meet after 6 hours.

Q14. The Average Monthly Income Of P And Q Is Rs. 505

Let P, Q and R represent their respective monthly incomes.

Then, we have:

P + Q = (5050 * 2) = 10100 --- (i)

Q + R = (6250 * 2) = 12500 --- (ii)

P + R = (5200 * 2) = 10400 --- (iii)

Adding (i), (ii) and (iii), we get: 

2(P + Q + R) = 33000 = P + Q + R = 16500 --- (iv)

Subtracting (ii) from (iv), we get, P = 4000.

P's monthly income = Rs. 4000.

Q15. A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And Then B Alone Finishes The Work In 42 Days. The Two Together Could Complete The Work In?

A’s 10 days work = (10 x 1/80) = 1/8 

Remaining work = (1 -1/8) = 7/8 

Therefore 7/8 work is done by A in 42 days. 

Whole work will be done by A in (42 x 8/7)i.e.., 48 days 

Therefore, (A+ B)’s 1 day work = (1/80 + 1/48) = 8/240 = 1/30. 

A and B together can finish it in 30days.

Q16. A, B And C Contract A Work For Rs. 55

Work to be done by C = (1 – 7/11) = 4/11 

Therefore, (A +B) = C = 7/11 : 4/11 = 7 : 4 

Therefore C’s share = Rs.(550 x 4/11) = Rs. 200.

Q17. A Tank Is Filled By Three Pipes With Uniform Flow. The First Two Pipes Operating Simultaneously Fill The Tank In The Same During Which The Tank Is Filled By The Third Pipe Alone. The Second Pipe Fills

Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.

1/x + 1/(x - 5) = 1/(x - 9)

(2x - 5)(x - 9) = x(x - 5) 

x2 - 18x + 45 = 0 

(x- 15)(x - 3) = 0 => x = 15.

Q18. A Can Finish A Work In 18 Days B Can Do The Same Work In 15 Days. B Worked For 10 Days And Left The Job. In How Many Days, A Alone Can Finish The Remaining Work?

B's 10 day's work = 1/15 * 10 = 2/3

Remaining work = (1 - 2/3) = 1/3

Now, 1/18 work is done by A in 1 day.

1/3 work is done by A in (18 * 1/3) = 6 days.

Q19. Kruti Took A Loan At Simple Interest At 6 % In The First Year With An Increase Of 0.5 % In Each Subsequent Year. She Paid Rs. 3375 As Interest After 4 Years. How Much Loan Did She Take?

Let the loan taken be Rs. X , then 

X × 6/100 × 1 + X × 6.5/100 × 1 + X × 7/100 × 1 + X × 7.5/100 × 1 = 3375 

=> (6+ 6.5 +7 +7.5) × X/100 = 3375 

=> X = (3375 × 100/27) = 12500.

Q20. Salaries Of Ravi And Sumit Are In The Ratio 2:

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively. 

Then, (2x + 4000)/(3x + 4000) = 40/57 

6x = 68000 => 3x = 34000

Sumit's present salary = (3x + 4000) = 34000 + 4000 = Rs. 38,000.

Q21. Two Pipes A And B Together Can Fill A Cistern In 4 Hours. Had They Been Opened Separately, Then B Would Have Taken 6 Hours More Than A To Fill Cistern. How Much Time Will Be Taken By A To Fill The Cis

Let the cistern be filled by pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1/x  + 1/(x + 6) = 1/4 

x2 - 2x - 24 = 0 

(x - 6)(x + 4) = 0 => x = 6.

Q22. Simple Interest On Rs.500 For 4 Years At 6.25 % Per Annum Is Equal To The Simple Interest On Rs. 400 At 5 % Per Annum For A Certain Period Of Time. The Period Of Time Is?

Let the required period of time be x years. 

Then 500 x 4 x 6.25/100 = 400 x 5/100 × x 

=> 20 x 6.25 = 20 × x 

=> X = 6.25 = 625/100 = 25/4 = 6 ¼ years.

Q23. A Sum Of Money Is To Be Distributed Among A, B, C, D In The Proportion Of 5:2:4:

Let the shares of A, B, C and D be 5x, 2x, 4x and 3x Rs. respectively. 

Then, 4x - 3x = 1000 => x = 1000.

B's share = Rs. 2x = 2 * 1000 = Rs. 2000.

Q24. A Can Do A Price Of Work In 30days While B Can Do It In 40 Days. In How Many Days Can A And B Working Together Do It?

(A +B)’s 1 day’s work = (1/30 + 1/40) = 7/120

Time is taken by both to finish the work = 120/7 days 

= 17 1/7 days.

Q25. A Cricketer Has A Certain Average For 10 Innings. In The Eleventh Inning, He Scored 108 Runs, There By Increasing His Average By 6 Runs. His New Average Is?

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6 

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs.

Q26. Ratio Of The Earnings Of A And B Is 4:

Let the original earnings of A and B be Rs. 4x and Rs. 7x.

New earnings of A = 150% 0f Rs. 4x = (150/100 * 4x) = Rs. 6x

New earnings of B = 75% of Rs. 7x = (75/100 * 7x) = Rs. 21x/4

6x:21x/4 = 8:7

This does not give x. So, the given data is inadequate.

Q27. Kabir Buys An Article With 25% Discount On Its Marked Price. He Makes A Profit Of 10 % By Selling It At Rs. 66

Original price be Rs. X 

C.P = (X – 25% of X) = 3X/4 

S.P = (3X/4 + 10% of 3X/4) = 33X/40= 660 

=> X = 800.

Q28. Two Pipes A And B Can Fill A Tank In 15 Min And 20 Min Respectively. Both The Pipes Are Opened Together But After 4 Min, Pipe A Is Turned Off. What Is The Total Time Required To Fill The Tank?

Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15

Remaining part = 1 - 7/15 = 8/15

Part filled by B in 1 minute = 1/20

1/20 : 8/15 :: 1 ; x

x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.

The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.

Q29. Subhash Purchased A Tape Recorder At 9/10th Of Its Selling Price And Sold It At 8% More Than Its S.p. His Gain Is?

S.P be Rs. X C.P paid by Subhash = Rs. 9X/10 

 S.P received by Subhash = Rs. (108% of Rs. X) 

 = Rs. 27X/25 

 Gain = Rs. (27X/25 – 9X/10) 

 = Rs. 9X/50 Gain = (9X/50 × 10/9X × 100)% = 20%.

Q30. A Large Tanker Can Be Filled By Two Pipes A And B In 60 And 40 Minutes Respectively. How Many Minutes Will It Take To Fill The Tanker From Empty State If B Is Used For Half The Time And A And B Fill I

Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24

Suppose the tank is filled in x minutes.

Then, x/2(1/24 + 1/40) = 1

x/2 * 1/15 = 1 => x = 30 min.

Q31. Bombay Express Left Delhi For Bombay At 14.30 Hours. Travelling At A Speed Of 60kmph And Rajadhani Express Left Delhi For Bombay On The Same Day At 16.30 Hours Travelling Speed Of 80kmph. How Far Away

Let the train meet at a distance of x km from Delhi.

Then x/60 –x/80 = 2 

=> 4x -3x 

=> x =480 

Therefore, Required distance = 480km.

Q32. R And S Start Walking Towards Each Other At 10 Am At Speeds Of 3km/hr And 4km/hr Respectively. They Were Initially 17.5km Apart At What Time Do They Meet?

Suppose they meet after x hours , then 3x +4x = 17.5 

=>  7x = 17.5 

=> X = 2.5hours 

So they meet at 12: 30 p.m.

Q33. Rs.6000 Becomes Rs.7200 In 4 Years At A Certain Rate Of Interest. If The Rate Becomes 1.5 Times Of Itself. The Amount Of The Same Principle In 5 Years Will Be?

S.I on Rs. 600 for 4 Years = Rs (7200 - 600) = Rs 1200 

Therefore Rate = (120000/24000) % p.a = 5 % p.a 

New Rate = (5 x 3/2) % = 15/2 % p.a 

Required Amount = [6000 + (6000 x 5/100 x 15/2)] 

= Rs(6000 + 2250) = Rs 8250.

Q34. A Cricketer Whose Bowling Average Is 12.4 Runs Per Wicket Takes 5 Wickets For 26 Runs And There By Decreases His Average By 0.

Let the number of wickets taken till the last match be x. Then,

(12.4x + 26)/(x + 5) = 12

= 12.4x + 26 = 12x + 60

= 0.4x = 34 

= x = 340/4 = 85.

Q35. Seats For Mathematics, Physics And Biology In A School Are In The Ratio 5:7:

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of increased sears are (140% of 5x), (150% of 7x) and (175% of 8x)

i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x)

i.e., 7x, 21x/2 and 14x

Required ratio = 7x:21x/2:14x

= 14x : 21x : 28x = 2:3:4.

Q36. The Average Weight Of A, B And C Is 45 Kg. If The Average Weight Of A And B Be 40 Kg And That Of B And C Be 43 Kg, Then The Weight Of B Is?

Let A, B, C represent their respective weights. 

Then, we have:

A + B + C = (45 * 3) = 135 --- (i)

A + B = (40 * 2) = 80 --- (ii)

B + C = (43 * 2) = 86 --- (iii)

Adding (ii) and (iii),

we get: A + 2B + C = 166 --- (iv)

Subtracting (i) from (iv), we get: B = 31

B's weight = 31 kg.

Q37. If 40% Of A Number Is Equal To Two-third Of Another Number, What Is The Ratio Of First Number To The Second Number?

Let 40% of A = 2/3 B. Then,

40A/100 = 2B/3 => 2A/5 = 2B/3

A/B = (2/3 * 5/2) = 5/3

A:B = 5:3.

Q38. A Is 30% More Efficient Than B. How Much Time Will They, Working Together, Take To Complete A Job Which A Alone Could Have Done In 23 Days?

Ratio of times taken by A and B = 100:130 = 10:13

Suppose B takes x days to do the work.

x = (23 * 13)/10 = 299/10

A's 1 day work = 1/23; B's 1 day work = 10/299

(A + B)'s 1 day work = (1/23 + 10/299) = 1/13

A and B together can complete the job in 13 days.

Q39. The Ratio Of The Prices Of Three Different Types Of Cars Is 4:5:

Let the prices be 4X, 5X and 7 X rupees 

 7X – 4X = 60000 

=> X = 20000 

Required price = 5X = Rs. 100000.

Q40. The Speeds Of A And B Are In The Ratio 3:

The time taken by B =(x-20/60)hrs = (x-1/3)hrs 

Ratio of speeds = Inverse ratio of time taken 

Therefore 3: 4 =(x-1/3) : x 

=>3x-1/3x=3/4 

=> 12x -4 =9x 

=> 3x =4 

=> X=4/3 hrs. 

X=1 1/3 hours. 

Required time = 1 1/3 hrs.

Q41. The Captain Of A Cricket Team Of 11 Members Is 26 Years Old And The Wicket Keeper Is 3 Years Older. If The Ages Of These Two Are Excluded, The Average Age Of The Remaining Players Is One Year Less Tha

Let the average of the whole team be x years.

11x - (26 + 29) = 9(x - 1) 

= 11x - 9x = 46 

= 2x = 46 => x = 23 

So, average age of the team is 23 years.

Q42. If The Rate Of Interest Be 4% Per Annum For First Year 5% Per Annum For The Second Year And 6% Per Annum From The Third Year Then The Compound Interest Of Rs 10000 For 3 Years Will Be?

Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)] 

= Rs(1000 × 26/25 × 21/20 × 53/50) 

= Rs (57876/5) = Rs 11575.20 

C.I = Rs (11575.20 - 10000) = Rs 1575.20.

Q43. A Can Do (1/3) Of A Work In 5 Days And B Can Do (2/5) Of The Work In 10 Days. In How Many Days Both A And B Together Can Do The Work?

1/3 of work is done by A in 5 days

Therefore, whole work will be done by A in 15 days 

2/5 of work is done by B in 10 days 

Whole work will be done by B in (10 x 5/2) i.e.., 25 days 

Therefore (A + B)’s 1 day’s work = (1/15 + 1/25) = 8/75 

So both together can finish 75/8 days i.e.., 9 3/8 days.

Q44. The Ratio Between The Speed Of Two Trains Is 7: 8.if The Second Train Runs 400km In 5 Hours. The Speed Of The First Train Is?

Let the speed of the first train be 7x km/hr

Then the speed of the second train is 8x km/hr 

But speed of the second train = 400/5 km/hr = 80km/hr 

=> 8x =80 

=> X=10 

Hence the speed of first train is (7 x 10)km/hr = 70km/hr.

Q45. The Compound Interest On Rs 16000 For 9 Months At 20% P.a Compounded Quarterly Is?

P = Rs 16000, R = (10/2)% 

per quarter, t = 3 quarters 

C.I = Rs [16000 × (1+ 5/100)3-16000) 

= Rs [16000 × 21/20 ×21/20× 21/20- 16000)

=Rs (18522-16000)=Rs 2522.

Q46. The Ratio Of The Number Of Boys And Girls In A College Is 7:

Originally, let the number of boys and girls in the college be 7x and 8x respectively. 

Their increased number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22.