Let the number to be added be x
Then
7+x13+x=23
(7+x)3=2(13+x)
3x-2x=26-21
x=5
Hence the required number is 5
Let the required numbers be 3x and 5x
If 8 is added to each other
3x+8:5x+8=2:3
3x+85x+8=23
3(3x+8)=2(5x+8)
9x+24=10x+16
10x-9x=24-16
x=8
Thus the numbers are 3x=3(8)=24
5x=5(8)=40
Directly using the formula, when a value is increased by R% and then decreased by R%, then net there is ( R∧2)/100 decrease. Putting R = 10, we get 1% decrease.
18/3 + 104/13 = 14
Cost price of bed= Rs.2400
Let's take market price of bed = X
As the question
C.P= (X-20X)/100
C.P= 80*X/100 -> 2400=8*X/10
X = Rs.3000.
-> S.P = 3000 ? (16*3000)/100
Selling Price = 2520
-> Profit = 2520- 2400 ==> 120Rs.
%profit = 120*100/2400= 5%
As per question, the average age of five girls is 15, Lets X be the total age of the girls
X/5= 11
X= 55
Oldest girl age+ remaining 4 girls age= 55
Remaining 4 girls age= 55-15==> 40
Average age of 4 girls = 40/4= 10 years.
Volume = πr2h
π*4*4*hA / π*5*5*hB = 12/25
Solving, hA/ hB = 3:4
Let take current age of Ram= x, current age of father = 3x
After 10 years, Ram age = x+10, Father's age= 3x+10
As per condition:
3x+10= 2*(x+10)
3x+10 = 2x+20
X= 10 years
Two numbers are in the ratio=2:7
Sum of the numbers=810
We have,
Sum of the terms in the ratio=2+7=9
First number=29×810
=2×90
=180
Second number=79×810
=7×90
=630
C.P = 1265*100*100*100/110/115/125
C.P = 800
series in the form of 5*1+1^3=6,
6*2+2^3=20,
20*3+3^3=87,
87*4+4^3=412,
412*5+5^3=125.
x:y=3:5
xy=35
5x=3y
x=3y5
3x+4y:8x+5y=3×3y5+4y:8×3y5+5y=9y+20y5:24y+25y5=29y5:49y5=29y:49y=29:49
Let's the number of pages typed in one hour by P, Q and R be p, q and r respectively. Then,
P,Q and R typed page in 1 hrs = 216/4
=> p + q + r = 216/4
=> p + q + r = 54 ...(i)
r - q = q - p => 2p = q + r ...(ii)
5r = 7p => p = 5/7 r ...(iii)
By Solving above (i), (ii) and (iii) equations
=> p = 15, q = 18, q = 21
Let the required numbers be 7x and 11x
If 7 is added to each of the numbers it becomes
7x+711x+7=23
21x+21=22x+14
X=21-14=7
Thus
The numbers are 7x=7×7=49
11x=11×7=77
Since the year is not leap year hence odd day will be = 1 day
So 1's day of next year will be = (Monday+ odd day) => Tuesday
So last day of that year = Monday
Suppose man's usual speed = s, and usual time = t
So distance = speed *time ==> d= s*t
If he travels with 5/6th of his usual speed which is = s*5/6
And time= (t+15) and distance, d = (s*5/6)*(t+15) {as distance will be same}
s*t = (s*5/6)*(t+15)
t= (5t+75)/6
t= 75 min.
We have
Sum of the terms of the ratio=2+3=5
Ravish money=25×1350
=2×270
=Rs.540
Shikha money=35×1350
=3×270
=Rs.810
(483*483*483+ 517*517*517) / (517*517 - 517*483 + 483*483) a3+b3
= (a+b)(a2-ab+b2) Hence [(a+b)(a2-ab+b2)] / (a2-ab+b2)
= a+b In the given equation a=483 and b= 517
==> 483+517=1000.
X% of SP = 34% of CP
Also, P = 26% of SP
SP - CP = 0.26(SP)
CP = 0.74(SP)
Now, (34/100)×74
X = 25.16
A & B one day work = 1/8
A alone one day work = 1/12
B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24)
=> B one day work = 1/24
so B can complete the work in 24 days.
Let ‘x’ be the monthly salary, then
(65/100 × 40/100)x + 35/100x = 43920
Solving, X= 72000
We have
Sum of the terms of the ratio=2+3+5=10
P-share= 210×totalmoney=210×2000=2×200=Rs.400
Q-share= 310×totalmoney=310×2000=3×200=Rs.600
R-share= 510×totalmoney=510×2000=5×200=Rs.1000
Given that
Three numbers are in ratio 2:3:5
Sum of these numbers=800
Sum of the terms of the ratio=2+3+5=10
Firstnumber=210×800=160Secondnumber=310×800=240Thirdnumber=510×800=400
Let the required ages be 5x and 7x
18 years ago their age ratios
5x−187x−18=813
65x−13×18=8×7x−8×18
65x-234=56x-144
65x-56x=234-144
9x=90
x=10
Thus the ages are 5x=5×10=50years
7x=7×10=70 years
x:y=8:9
xy=89
9x=8y
x=8y9
7x−4y:3x+2y=7×8y9−4y:3×8y9+2y=56y−36y9:42y9=20:42=10:21
For one year the capital is
A = (40500 * 6 + 45000 * 6) = Rs. 5,13,000
B = (45000 * 12) = Rs. 5,40,000
C = (60000 * 6 + 45000 * 6) = Rs. 6,30,000
Ratio A : B : C = 513 : 540 : 630
C's share will exceed that of A by
= [(630 - 513)/1683] * 56100 => (117/1683) * 56100
=> (117/3) * 100 = 39 * 100 = Rs. 3900
Total cost price of 40 shirts including trportation = 3000+ (3000*10)/100 = 3300
Given profit = 20%
Hence, Selling price = (100+20)*3300/100
S.P of 40 shirts = 3960
So S.P. of 1 shirt = 3960/40= Rs.99
35% of 30=25% of X+1
35*30/100= 25*X/100+1
105/10=X/4 +1
X=38
LEADING word can be written as "L" "E" "A" "D" "I" "N" "G"
Taking vowels together = E A I, so vowels can be arranged as= !3 ways and lets Vowels be a unit X
So X L D N G, It can be arranged in = !5 Ways
So complete word can be written in= !3 *! 5 = 720 ways
(A+B)'s 1-day work, when working together= 1/30
(A+B)'s 20 days' work= 20/30==> 2/3
Remaining work = (1-2/3) ===> 1/3
Remaining work was done by A in 20 more days = 1/3
So A can complete the whole work alone in = 20* 3 ===>60 days
Hence A's 1-day work, working alone = 1/60
B?s 1 day work, working alone = 1/30-1/60======1/60
So B will take 60 days to for completing the entire word.