310 x 999 = 310 x (1000-1)
= 310 x 1000 -310 x 1
= 310000 – 310
= 309690.
125% ---- 3400
=> 100% ---- ?
=> ? = 3400x100/125 = 2720
=> Cost price of the article = Rs. 2720
Profit when article sold at Rs. 3265 = 3265 - 2720 = 545
Hence, Profit% = Gain x 100/cost price
=> P% = 545 x 100/2720
=> P% = 20%.
Let the third number = N
Then the first number = 3N
And second number = 3N/2
According to the question [N + 3N + 3N/2] / 3=154.
Let C.P.= Rs. 100.
Then, Profit = Rs.220,
S.P. = Rs.320.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs.320.
Profit = Rs. (320 - 125) = Rs. 195
Required percentage = 195/320×100== 60.9 =~ 61%.
Let the cost price be x and selling price be y.
Loss = x – y
When the cost price doubles, the loss gets tripled.
So it becomes like this, 2x – y = 3(x-y)
=> x = 2y
Loss % = (loss/ C.P) x 100 = [(2y-y)/2y] x 100= 50 %.
The given number is 1, 3, 5………….99
This is an A.P with a = 1, d = 2
Let it contain n term 1 + (n-1)2 = 99
==> n = 50
Then required sum = n/2 (first term + last term)
==> 50/2(1 + 99) = 2500.
Sum = Rs.(50*100)/2*5=Rs.500
Amount=Rs.[500*(1+5/100)2]
= Rs. 551.25
C.I = Rs.(551.25-500)= Rs.51.25.
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30.
Let the distance between home and school is 'x'.
Let actual time to reach be 't'.
Thus, x/4 = t + 4 ---- (1)
and x/6 = t - 30 -----(2)
Solving equation (1) and (2)
=> x = 98 mts.
The formula to calculate simple interest is :
SI=(P x T x R)/100
In the given question Principal(P)=Rs. 14000, Time(T)=(3/12)yr. and Rate of interest(R)=10%
So, SI=(14000 x 1/4 x 10)/100
SI= Rs. 350.
Let Cost Price(C.P) = P
gain% = {(S.P-C.P)/C.P} x 100
25 = {(1540-P)/P} x 100
25/100 = (1540-P)/P
=> P = 4(1540)-4P
=> 5P = 4(1540)
=> P = 1232
So, Cost Price = Rs. 1232.
90 = 10 x 9
Clearly, 653xy is divisible by 10, so y = 0
Now, 653x0 is divisible by 9.
So, (6 + 5 + 3 + x + 0) = (14 + x) is divisible by @So, x = 4.
Hence, (x + y) = (4 + 0) = 4.
We know 60 min = 1 hr
Total northward Laxmi's distance = 20kmph x 1hr = 20 km
Total southward Prasanna's distance = 30kmph x 1hr = 30 km
Total distance between Prasanna and Laxmi is = 20 + 30 = 50 km.
Say total cost price of tea is x.
Then total profit at a rate of 15% is = (15x/100)
According to question,
15x/100 = 60
so x = 400
C.p of the tea is Rs. 400.
so total selling price will be = (400+60) = Rs.460
so the quantity of the tea will be = (460/5.75) = 80kg.
Dividend = 12 * 35 =420
Now dividend = 420 and divisor = 21
Therefore correct quotient = 420/21 = 20.
Let x men can do the in 12 days and the required number of days be z
More men, Less days [Indirect Proportion]
Less work, Less days [Direct Proportion ]
men2x:xwork1:12} :: 12 : z
(2x×1×z)=(x×12×12)
z=3.
Let Rs. K invested in each scheme
Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%
Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%
Now,
(P x 44/100) - (P x 32.25/100) = 528.75
=> 11.75 P = 52875
=> P = Rs. 4500
Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
Divisor = (5 x 46) = 230
10 x Quotient = 230=230= 23/10
Dividend = (Divisor x Quotient) + Remainder
= (230 x 23) + 46
= 5290 + 46
= 5336.
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons30:39Working hours/day6:5}?? 12:x
=> 30 * 6 * x = 39 * 5 * 12
=> x= 13.
As we know that Speed = Distance / Time
for average speed = Total Distance / Total Time Taken
Thus, Total Distance = 325 + 470 = 795 km
Thus, Total Speed = 7.5 hrs
Average Speed = 795/7.5 => 106 kmph.
Let x = 6q + 3.
Then, x2 = (6q + 3)2
= 36q2 + 36q + 9
= 6(6q2 + 6q + 1) + 3
Thus, when x2 is divided by 6, then remainder = 3.
Less Men, me more Days {Indirect Proportion}
Let the number of days be x then,
27 : 36 :: 18 : x
[Please pay attention, we have written 27 : 36 rather than 36 : 27, in indirect proportion, if you get it then chain rule is clear to you :)]
=>27x = 36 * 18
=> x = 24
So 24 days will be required to get work done by 27 men.
Average speed = Total distance / Total time.
Total distance traveled by Joel = Distance covered in the first 3 hours + Distance covered in the next 5 hours.
Distance covered in the first 3 hours = 3 x 60 = 180 miles
Distance covered in the next 5 hours = 5 x 24 = 120 miles
Therefore, total distance traveled = 180 + 120 = 300 miles.
Total time taken = 3 + 5 = 8 hours.
Average speed = 300/8 = 37.5 mph.
we know that 1 mile = 1.6 kms
=> 37.5 miles = 37.5 x 1.6 = 60 kms
Average speed in Kmph = 60 kmph.
Since the car runs at 7/11 th of its own speed, the time it take is 11/7th of its usual speed.
let the usual time taken be t hours
then we can write, 11t / 7 = 22
or t = 22 * 7 / 11 = 14 hours
Time saved = 22 - 14 = 8hours.
Let d = divisor and q = quotient
First remove the last remainder:
d x q + 413 = 380606
d x q = 380193.
Let the number be P and Q
According to the question
(P + Q) = 2.5 (P - Q)
P + Q = 2.5P - 25Q
3.5Q = 1.5P
P / Q = 7/3 .....(i)
Now PQ = 84.
Speeds of two trains = 30 kmph and 58 kmph
=> Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s
Given a man takes time to cross length of faster train = 18 sec
Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.
The only part of this type of calculation that needs particular
care is that concerning the interest rate. The formula assumes that
r is a proportion, and so, in this case:
r = 0.08
In addition, we have P = 5,000 and n = 5, so:
V = P(1 + r)5 = 5,000 x (1 + 0.08)5 = 5,000 x 1.469328 = 7,346.64
Thus the value of the investment will be 7,346.64.
Let the C.P be 'x'
Then, the selling price S.P = x - 16x/100
= 84x/100 = 21x/25
Now, if the S.P is 60 more, then the profit is 14%
=> 21x/25 + 60 = x + 14x/100
=> 114x/100 - 21x/25 = 60
=> (57 - 42)x/50 = 60
=> 15x/50 = 60
x = 3000/15 = 200
Therefore, the Cost price C.P = x = Rs. 200.
Let 'd' be the distance between A and B
K -time = d/10 + d/9 = 19d/90 hours
L -time = 2d/12 = d/6 hours
We know that, 10 min = 1/6 hours
Thus, time difference between K and L is given as 10 minutes.
=> 19d/90 - d/6 = 1/6
=> (19d-15d)/90 = 1/6
=> 4d/90 = 1/6
Thus,
d= 15/4 km = 3.75 km.
hence the distance between A and B is 3.75 km.
Time taken to cover 600 km = 600/100 = 6 hrs.
Number of stoppages = 600/75 - 1 = 7
Total time of stoppages = 4 x 7 = 28 min
Hence, total time taken = 6 hrs 28 min.
Let first number = P
And second number = Q
According to the question
P - Q = 10 ....(i)
And 3P - 4Q = 18...(ii)
on multiply eq (i) by 3 and then subtract eq (ii) from it
3P - 3Q = 54
3P - 4Q = 18
Q = 36
On putting the value of Q in the eq (i)
P = 18 + Q = 18 +36
P = 54.
Amount
=Rs.[8000x(1+5/100)²]
= Rs.[8000 x 21/20x21/20]
= Rs.8820.
Initial speed = 80km/hr
Total distance = 80 * 10 = 800km
new speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr.
let 't' be the time after which they met since L starts.
Given K is 50% faster than L
50 t + 1.5*50(t-1) = 300
50 t +75 t = 300 + 75
t = 375 / 125 = 3 hrs past the time that L starts
So they meet at (9 + 3)hrs = 12:00 noon.
2056 x 987 = 2056 x (1000 - 13)
= 2056 x 1000 - 2056 x 13
= 2056000 - 26728
= 2029272.
net height climbed in 2 min = 20m - 4m = 16m
In 10 min the net height climbed = 16 * 10/2 = 80m
Remaining height = 96m - 80m = 16m
In the 11th min , the monkey will be ascending up.
Time taken to ascend the last 16min
16/20 = 4/5min
Total time taken = 10 + 4/5 = 54/5 min.
least cost price = 200*8 = 1600
greatest sold price = 425 * 8 = 3400
profit required = 3400- 1600 = 1800.
Average speed=total distance/total time
Let distance to store be K
then, total time =(K/20)+(K/30)=K/12
and, total time =(2K)
so average speed= 2K / (K/12) = 24kmph.
Let the C.P of one item is Rs. P
and that of other is Rs. (7500 - P)
According to the data given
C.P = S.P
=> Px(116/100) + (7500-P)x(86/100) = 7500
=> 30P = 105000
=> P = 3500
Required difference between selling prices
= Rs. [(3500/100) x 116] - [(4000/100) x 86]
= 4060-3440
= Rs. 620.
Length of train A = 48 x 9 x 5/18 = 120 mts
Length of train B = 48 x 24 x 5/18 - 120
=> 320 - 120 = 200 mts.
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000*(1+7/100)^n=34347
n= 2 years.
Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.
CP of 1000gm = Rs. 10
SP of 800gm = Rs. 12
SP of 1000gm =12x1000/800 = Rs. 15
Now take 1000gm as reference to calculate profit.
Profit=SP-CP=15-10=Rs. 5
Profit % = 5x100/10 = 50%.
Cost price of the article is given by
= 400x100/(20+20)
= Rs.1000.
Let x be the number and y be the quotient. Then,
x = 357 x y + 39
= (17 x 21 x y) + (17 x 2) + 5
= 17 x (21y + 2) + 5)
Required remainder = 5.
We know Compound Interest = C.I. = P1+r100t - 1
Here P = 2680, r = 8 and t = 2
C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225
= (2680 x 52 x 2)/625
= 445.95
Compound Interest = Rs. 445.95.
Let marked price = Rs. 100.
Then, C.P. = RS. 54,
S.P. = Rs. 85
Gain % = 31/64 x 100 = 48.4%.
Let the distance travelled by Tilak in first case or second case = d kms
Now, from the given data,
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hrs
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.
When 3 passengers income was 3x
expense= Rs.30
profit =20% of 30 = Rs.6
That me his earning is Rs.3@so that per passenger fare must be Rs.12.
When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%.