Cost of each eraser = (36 + 8 -40) = Rs.4
Required amount = 15 * 36 + 12 * 45 + 10 * 8 + 5 * 4
540 + 540 + 80 + 20 = Rs.1180
Let total fair rs.2400
C share=10/24*2400=1000
Distance=125 meter speed=50-5=45km/hr=>45*5/18=12.5 m/s
Time=125/12.5=10sec
Speed upstream = 7.5 km ph.
Speed downstream = 10.5 km ph.
Add up to time taken = 105/7.5 + 105/10.5 hours = 24 hours.
B is thrice as fast as C
C covered in 42 minutes
B covered in 42/3=14 min
Since A beats B by 200 m or 25 seconds, it implies that B covers 200 m in 25 seconds.
Hence speed of B = 200/25 = 8 m/s.
A runs B runs C runs
600 meters race 600 m 540 m
500 meters race 500 m 450 m
Coming ratio A runs B runs C runs
300 meters-2700 meters-2430 meters
Unitary A runs B runs C runs
Methods 400m-360m-324m
A beat C by 400- 324=76 meters.
The least number which when divided by different divisors leaving the same remainder in each case
= LCM(different divisors) + remainder left in each case.
Hence the required least number
= LCM(35, 11) + 1 = 386.
20 men in 6 days can build 112 meters
25 men in 30 days can build=112*(25/20)*(3/6)
= 70 meters
Give the times of youngsters a chance to be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
At that point, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Let CP=100, SP=70
Loss= 30/70*100=42.85%
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Fifteenth August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 jump years + 7 customary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.
Jan. Feb. March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Add up to number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
(5m + 9w)10 = (6m + 12w)8
=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m
8 men can do the work in 10 days.
3m +3w = 3m + 1w = 4m
So, 4 men can do the work in (10 * 8)/4 = 20 days.
Let the first number and the second number be F and S respectively.
5/2 F = 48/100 S —-> (1)
S = 1/9 * 1125 = 125
(1) => 5/7 F = 48/100 * 125
=> F = 84
25% of F = 1/4 * 84 = 21.
Speed = 20 m/sec.
Time = 26 sec.
Then, x + 250 /26= 20
x + 250 = 520
x = 270.
Part filled by (A + B + C) in 3 minutes = 3 (1/30+1/20+1/10)= 3*11/60=11/20
Required proportion = 3/10 x 20/11 = 6 /11
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
For dealing with, A got = 5% of Rs. 7400 = Rs. 370.
Equalization = Rs. (7400 - 370) = Rs. 7030.
Proportion of their investment = (6500 x 6): (8400 x 5): (10000 x 3)
= 39000: 42000: 30000
= 13: 14: 10
B's offer = Rs. 7030 x14/37= Rs. 2660.
Every one of the numbers aside from 14 is an odd number.
The number '14' is the main EVEN number.
Assume initially he had x apples.
At that point, (100 - 40)% of x = 420.
60/100 x x = 420
x = 420 x 100 = 700.
Principal = Rs. 100 x 5400/1200x3 = Rs. 15000.
8820 —- 441
100 —- ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000
Each number is double the former one with 1 included or subtracted then again.
Along these lines, the following number is (2 x 261 + 1) = 523.
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = occasion of getting at most two heads.
At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P (E) = n (E)/n(S) = 7/8
Average mark scored by all the three boys =
[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for a long time = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs. 6150.
Give the number of notes of every division a chance to be x.
At that point x + 5x + 10x = 480
16x = 480 x = 30.
Consequently, add up to number of notes = 3x = 90
Let x=speed of boat and y=speed of current
=30/ (x + y) =18/(x-y) =5 by solving y=1.2 km/hr
So we have C.P. = 29.50
S.P. = 31.10
Gain = 31.10 - 29.50 = Rs. 1.6
Gain %=( Gain/Cost*100)%
= (1.6/29.50?100)%=5.4%
Relative speed = (120 + 80) km/hr
= 200 x 5/18 m/sec
= 500/9 m/sec.
Let, S = {1, 2, 3, 4, 19, 20}.
Let E = event of getting a few of 3 or 5 = {3, 6, 9, 12, 15, 18, 5, 10, 20}.
P (E) = n (E)/n(S) = 9/20
At that point, remove canvassed upstream in 8 hrs. 48 min = Distance covered downstream in 4 hrs.
X* 8 4 /5= (y x 4)
44/5 x =4y
y = 11/5 x.
Required proportion = y + x/2: y - x /2
= 16/5 x 1/2: 6/5 x 1/2
= 8/5:3/5
= 8: 3.
Give the number of notes of every group a chance to be x.
At that point x + 5x + 10x = 480
16x = 480
x = 30.
Consequently, add up to number of notes = 3x = 90.
25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000
P(SnK) = P(S) + P(K) – P(SnK), where S denotes spade and K denotes king.
P(SnK) = 13/52 + 4/52 – 1/52 = 4/13
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
LCM of 16, 20, 25, 45 = 3600
1 * 3600 + 3 = 3603 not divisible by 21
2 * 3600 + 3 = 7203 is divisible by 21